When a liquid is placed in a container, it exerts force on the bottom as well as on the walls of the container. The force (weight) of the liquid on per unit area of the container is called the liquid pressure.
Depth of the liquid (h), density of liquid (d) and acceleration due to gravity (g) are the three factors that affect the pressure due to liquid contained in a vessel.
In this case the tank with smaller base will exert more pressure because to contain same volume of liquid as the broad base tank the height of the tank with smaller base must be larger than the height of the tank with broader base. And according to the liquid pressure law as the height increases the pressure exerted by liquid increases.
The pressure due to liquid at the downstairs tap will be higher than the upstairs tap as according to liquid pressure law pressure exerted by liquid is directly proportional to height of the liquid column. Due to high pressure the water will flow with more force, at the lower tap, filling the bucket faster than the tap upstairs.
The pressure exerted by a liquid is directly proportional to the depth of the liquid, as we go deeper into the bottom the pressure increases. So withstand the large pressure at the bottom of the dam the wall in a dam is made comparatively thicker than at the surface. If the wall is thin then the risk of dam break is higher.
The height (h) of the blood column at the feet is large as compared to at the brain . Hence, blood pressure is more at feet that at the brain according to this formula, p=hdg where d = density of the medium(blood).

Solution,

Weight of body in liquid= 10N

Weight of displaced liquid= 2N

Weight of body in air=?

Using formula,

Weight of body in air= weight of body in liquid+ weight of displaced liquid

= 10+2

=12N

Upthrust= Weight of displaced liquid

= 2N

For mass of body,

Weight of body in air(W)=12N

Acceleration due to gravity= 10m/s2

Mass of the body (m)=?

Using formula,

\begin{align*}m &=\frac{W}{g}\\ &= \frac{12}{10}\\&=1.2 \: kg. \end{align*}

Here,

Weight of stone in water= 9N

Weight of displaced water= 2N

Weight of stone in air=?

We know,

The weight of stone in air= Wt. of stone in water+ Wt. of displaced water

=9N +2N

=11N

Solution,

Upthrust of water=Weight of displaced water

=10N

Now,

Weight of stone in water=40N

Weight of displaced water =10N

Weight of stone in air=Wt. of stone in air+ Wt. of displaced water

=40N + 10N

= 50N

Here,

The weight of iron in air= 20N

The weight of iron in water= 12N

The weight of water displace by iron= ?

we know,

The weight of water displaced by iron=wt of iron in air- wt of iron in water

=20N-12N

=8N

The upthrust on the iron= weight of displaced water = 8N

Upthrust = Wt. of displaced water

∴8N=8N

Here,

Wt. of stone in water= 3N

Wt. of displaced water= 5N

we know that,

The wt. of stone in air= Wt. of stone in water+wt. of displaced water

=3N+ 5N

=8N

Again,

Upthrust= Weight in air- Weight in water

=8N-3N

=5N

Hence, upthrust of water is 5N and the weight of stone in air is 8N.

Here,

Weight of the object in air (Wa) =34N

Weight of the object in water (Ww) =10N

Upthrust = ?

Weight of the water displaced (W2) =?

We know that,

Upthrust = Wa-Ww

= 34-10

= 24N

Again,

We know,

Upthrust (U) = Weight of the liquid displaced(W2)

∴ the weight of the liquid displaced =24N

Thus, upthrust on the body is 24N and weight of displaced fluid is 24N.