Practice Test | Kullabs.com
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  • If sin 9° ×  sin 27° = cos 63° × cos 81° then, what's it identity value?

    tan 63° × cos 81°
    sin 63° × cos 81°
    sin 63° ×tan 81°
    cos 63° × cos 81°
  • What is the value of this identity sin1°. sin2°. sin45° .sec88° .sec89° ?

    3
    1
    -1
    2
  • sec( heta).cosec(90° - ( heta)) - tan( heta).cot(90° - ( heta))

    -1
    3
    -2
    1
  • (frac{cos(90°+θ).sec(-θ).tan(180° - θ)}{sec(360° + θ).sin(180°+θ).cot(90°-θ)})

    -1
    -2
    1
    2
  • What is the numerical value of sin70°.cos20° + sin20°.cos70°?

    sin270° + cos270° = 1
    cos270° + tan270° = 1
    sin270° + cos270° = -1
    sin270° + cos270° = -1
  • What is the identical value of sin 240°?

    (frac{sqrt{3}}{2})      
    -(frac{1}{sqrt{2}})      
    -(frac{sqrt{3}}{2})           
    (frac{1}{sqrt{2}})      
  • What is the numerical value of tan(-300°)?

    (sqrt{2})
    (sqrt{3})
    -(sqrt{3})
    -(sqrt{2})
  • sin(90° - A) = _______

    sec A
    sin A
    tan A
    cos A
  • cos(90° - A)= _______

    cos A
    sin A
    cosec A
    cot A
  • tan(90° - A) =_______

    cot A
    sec A
    cosec A
    tan A
  • cosec(90° - A)= _______

    sec A
    cot A
    sin A
    cosA
  • sec(90° - A)= _______

    cosec A
    cot A
    cos A
    sin A
  • cot(90° - A)= _______

    cot A
    tan A
    sinA
    cos A
  • sin(90° + A) =  _______

    sin A
    cos A
    tan A
    cosec A
  • cos(90° + A)=  _______

    ;i:1;s:13:
    
    cos A
    sin A
  • tan(90° + A) =  _______

    sin A
    ;i:1;s:11:
    
    
  • cosec(90° + A)=  _______

    
    ;i:3;s:5:
    ;i:2;s:5:
    sec A
  • sec(90° + A)=  _______

    ;i:1;s:13:
    cot A
    tan A
    
  • cot(90° + A)=  _______

    
    ;i:2;s:7:
    ;i:3;s:5:
    ;i:1;s:5:
  • sin(180° - A) = _______

    ;i:3;s:5:
    sin A
    
    ;i:2;s:5:
  • tan(180° - A) = _______

    
    ;i:1;s:4:
    ;i:2;s:5:
    ;i:3;s:5:
  • cosec(180° - A)= _______

    cos A
    secA
    cosec A
    sin A
  • sec(180° - A)= _______

    
    
    ;i:1;s:11:
    cot A
  • cot(180° - A)= _______

    ;i:1;s:11:
    
    tan A
    
  • tan(180° + A) = _______

    cos A
    sin A
    cot A
    tan A
  • sec(180° +A)= _______

    cot A
    sin A
    sec A
    cosec A
  • cot(180° +A)= _______

    cos A
    sin A
    cot A
    tan A
  • tan(270° - A) = _______

    cot A
    sin A
    cosec A
    cos A
  • cot(270° - A)= _______

    cos A
    cosc A
    tan A
    sin A
  • cos(270° +A)= _______

    sin A
    tan A
    cosec A
    cos A
  • sec(270° + A)= _______

    sin A
    cos A
    secA
    cosec A
  • cos(360° - A)= _______

    sec A
    tan A
    sin A
    cos A
  • sec(360° - A)= _______

    cosec A
    sec A
    sin A
    cot A
  • cos(-A)= _______

    cos A
    sec A
    sin A
    tan A
  • sec(-A)= _______

    sec A
    tan A
    sin A
    cosec A
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